I've become aware of N-ethyl 4-bromo-2,5 dimethoxy phenethylamine as well as N-Methyl-2,5-dimethoxy-4-iodophenethylamine. I obviously know the activity of 2c-i and 2c-b and was curious about how the ethylated/methylated counterparts would compare in terms of activity and effects. Can anyone with a background in pharmacology/chemistry help?
Im pretty sure N-Methyl-2C-I is inactive, and Im assuming the 2C-B analogue will be too. I think I know where you found out about these and my advice is stay away from that place....
You probably do know where I found these. I had read somewhere else that the methyl-2ci would be inactive, but noone seems to know from a pharmacological standpoint why that would be.
Unfortunantly I cant help you with a detailed reason as to why theyre not active, perhaps try posting at BL if no one here has an answer
I highly doubt anybody can actually answer your question since it is still not known precisely how the vast majority of psychedelics work. The most obvious reason why methyl-2c-b does not work is that the shape of N-Methyl-2c-b causes it to not be able to bind to the same receptors (or maybe just not nearly as effectively). There are alot of really weird things in psychedelic chemistry. For instance 5-meo-det causes unpleasant vertigo, while n,n-det, and 5-meo-dmt are both quite similiar in action to n,n-dmt (I don't know from experience). Even more baffling is that 5-meo-dipt is a very powerful psychoactive drug while DiPT basically only causes auditory hallucinations.
The reason it's not psycho active can be addressed- but it's highly technical. Don't waste your time. Synthetic PEA's have no spritual/pragmatic value. Stick with mescaline and MDA ( like you can get them!) Or go with tryptamines and econines(SP?) With the exception of mescaline, tryps are where it's at.
5meo-dipt also has auditory affects. Perhaps the 5meo addition lowers the dose required for all affects except the ones affecting hearning. Auditory affects seem clearly related to the Dipt homologs, while adding a 5meo group simply increases both potency and negative side affects. Why this is true I don't begin to understand.
I'm not a kid. I wouldn't have asked the question if I wasn't looking for an explanation. I'll decide how to spend my time, so if you can answer the question, why don't you stick to that. Thanks
This doesn't answer your question, but it seems interesting that the n,methyl versions are much less active in the phychedelic amphetamines, yet more active when the drug is primarily a stimulant (MDMA, meth).
